In a 4160 V four-wire system, what is the phase-to-ground (phase-to-neutral) voltage?

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Multiple Choice

In a 4160 V four-wire system, what is the phase-to-ground (phase-to-neutral) voltage?

Explanation:
In a four-wire system with a neutral, the phase-to-ground voltage is the same as the phase-to-neutral voltage. For a balanced three-phase system, the line-to-line voltage relates to the line-to-neutral voltage by V_LL = sqrt(3) × V_LN. So the phase-to-neutral (phase-to-ground) voltage is V_LN = V_LL / sqrt(3). With a line-to-line voltage of 4160 V, V_LN ≈ 4160 / 1.732 ≈ 2400 V. Therefore, the phase-to-ground voltage is about 2400 V. The other values don’t fit because 4160 V is the line-to-line voltage, not phase-to-neutral, and the division by sqrt(3) yields the 2400 V result, not 7200 or 9600.

In a four-wire system with a neutral, the phase-to-ground voltage is the same as the phase-to-neutral voltage. For a balanced three-phase system, the line-to-line voltage relates to the line-to-neutral voltage by V_LL = sqrt(3) × V_LN. So the phase-to-neutral (phase-to-ground) voltage is V_LN = V_LL / sqrt(3).

With a line-to-line voltage of 4160 V, V_LN ≈ 4160 / 1.732 ≈ 2400 V. Therefore, the phase-to-ground voltage is about 2400 V.

The other values don’t fit because 4160 V is the line-to-line voltage, not phase-to-neutral, and the division by sqrt(3) yields the 2400 V result, not 7200 or 9600.

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